Sum the series n-1- n-1 -2- n-2 -3-1-n- is n n-1 n-2 -6-If you think this is true write 1 otherwise write 0

T_r= ( n r+1 )r= ( n+1 )r r^2 ∴ S_n= ( n+1 )∑_r=1^nr ∑_r=1^nr^2 #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; ...

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Vn Method

Sum the serie...

Question

Sum the series $n .1 + (n - 1) .2 + (n - 2) .3 + . . . .1 . n .$ is $\frac{n (n + 1) (n + 2)}{6}$ .If you think this is true write 1 otherwise write 0

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