Sum the series (x+1x)2+(x2+1x2)2+(x3+1x3)2................+(xn+1xn)2
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Solution
Open the brackets and split into three series (x2+x4+x6+...)+(1x2+1x4+1x6+...)+(2+2+2+...) =x2(x2n−1x2−1)+1x2(1x2n−1)1x2−1+2n =x2(x2n−1)x2−1+x2n−1x2n.(x2−1)+2n =x2n−1x2−1[x2+1x2n]+2n =x2n−1x2−1[x2n+2+1x2n]+2n