CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
157
You visited us 157 times! Enjoying our articles? Unlock Full Access!
Question

Sum the series
(x+1x)2+(x2+1x2)2+(x3+1x3)2................+(xn+1xn)2

Open in App
Solution

Open the brackets and split into three series
(x2+x4+x6+...)+(1x2+1x4+1x6+...)+(2+2+2+...)
=x2(x2n1x21)+1x2(1x2n1)1x21+2n
=x2(x2n1)x21+x2n1x2n.(x21)+2n
=x2n1x21[x2+1x2n]+2n
=x2n1x21[x2n+2+1x2n]+2n

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sum of Coefficients of All Terms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon