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Byju's Answer
Standard XII
Mathematics
Geometric Progression
Sum the serie...
Question
Sum the series :
x
(
x
+
y
)
+
x
2
(
x
2
+
y
2
)
+
x
3
(
x
3
+
y
3
)
+
.
.
to n terms
Open in App
Solution
x
(
x
+
y
)
+
x
2
(
x
2
+
y
2
)
+
x
3
(
x
3
+
y
3
)
+
.
.
.
.
.
+
x
n
(
x
n
+
y
n
)
=
(
x
2
+
x
4
+
x
6
+
.
.
.
.
.
+
x
2
n
)
+
(
x
y
+
x
2
y
2
+
x
3
y
3
+
.
.
.
.
.
+
x
n
y
n
)
=
x
2
(
x
2
n
−
1
)
x
2
−
1
+
x
y
(
x
n
y
n
−
1
)
x
y
−
1
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0
Similar questions
Q.
Determine the sum of the series
x
(
x
+
y
)
+
x
2
(
x
2
+
y
2
)
+
x
3
(
x
3
+
y
3
)
+
.
.
.
.
.
.
.
to
n
terms.
Q.
x
(
x
+
y
)
+
x
2
(
x
2
+
y
2
)
+
x
3
(
x
3
+
y
3
)
+
.
.
.
.
to
n
terms.
Q.
Evaluate:
x
(
x
+
y
)
+
x
2
(
x
2
+
y
2
)
+
x
3
(
x
3
+
y
3
)
+
.......to n terms,
where
x
&
y
both less than
1
Q.
Given that |x|<1 and |y|<1, then find the sum of the series x(x+y) + x
2
(x
2
+y
2
) + x
3
(x
3
+y
3
)….
Q.
Evaluate
x
(
x
+
y
)
+
x
2
(
x
2
+
y
2
)
+
x
3
(
x
3
+
y
3
)
+
.
.
.
.
t
o
n
t
e
r
m
s
x
2
(
1
−
x
2
n
)
1
−
x
2
+
x
y
(
1
−
x
n
y
n
)
1
−
x
y
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