7,77,777,...
Sn=7+77+777+...
=7[1+11+111+...]
=79[9+99+999+...]
=79[(10−1)+(100−1)+(1000−1)+...]
=79[(10+100+1000+...aG.P.)−(1+1+...ntimes)]
=79[10(1−10n1−10)−n]
=79[10(1−10n−9)−n]
=79[10(10n−19)−n]
If the sum of first n terms of an A.P. be equal to the sum of its first m terms, (m≠n), then the sum of its first (m+n) terms will be
The sum of first 2n terms of A.P. 2, 5, 8, . . . is equal to the sum of first n terms of A.P. 57, 59, 61, . .. ., then n is equal to