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Question

Sum to infinite terms the following series:
1+4x+7x2+10x3+...,|x|<1.

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Solution

S=1+4x+7x2+10x3+... ..................(1)
Sx=x+4x2+7x3+.... ...............(2)

eqn(1)eqn(2), we get
(1x)S=1+3x+3x2+3x3+... .........(3)

This is a G.P. of common ratio =x

So, using sum of G.P.=a(1r)
Here, a=first term and r=common ratio

So,
(1x)S=1+3x(1x)

(1x)S=1x+3x(1x)

S=1+2x(1x)2

Hence, this is the answer.

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