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Byju's Answer
Standard XII
Mathematics
Sum of n Terms
Sum upto n ...
Question
Sum upto
n
the series
.7
+
.77
+
.777
+
.
.
.
.
.
.
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Solution
S
=
.7
+
.77
+
.777
+
.
.
n
terms
=
7
9
[
.9
+
.99
+
.999
+
.
.
.
.
]
=
7
9
[
(
1
−
1
10
)
+
(
1
−
1
100
)
+
(
1
−
1
1000
)
+
.
.
.
.
.
.
.
.
]
=
7
9
[
(
1
+
1
+
1
+
.
.
.
)
−
(
1
10
+
1
10
2
1
10
3
+
.
.
)
]
=
7
9
[
n
−
1
10
.
1
−
(
1
/
10
n
)
1
−
(
1
/
10
)
]
=
7
n
9
−
7
81
(
1
−
1
10
n
)
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