Superphosphate of lime is obtained by treating :

calcium phosphate with

H C l

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calcium phosphide with

H C l

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calcium phosphate with

H_{2} S O_{4}

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calcium phosphate with

N a O H

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Solution

The correct option is C calcium phosphate with $H_{2} S O_{4}$
$C a_{3} (P O_{4})_{2} + H_{2} S O_{4} \to 2 C a S O_{4} + C a (H_{2} P O_{4})_{2} s u p e r p h o s p h a t e o f l i m e$

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H_{3} P O_{4}

1

H_{2} S O_{4} ?

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