Question

Suppose 2 kg of sugar contains $9\times {10}^6$ crystals.

How many sugar crystals are there in

(i) 5 kg of sugar?

(ii) 1.2 kg of sugar? [2 MARKS]

Answer 1

Solution : 2 Marks

The ratio of weight of sugar to number of crystals remains a constant.

(i) Let the number of sugar crystals in 5 kg of sugar be x.
Since 2 kg of sugar contains $9\times {10}^6$crystals.

$So,\frac{2}{9\times {10}^6}=\frac{5}{x}$

$x=22.5\times {10}^{6}crystalsin5kgofsugar.$

(ii) Let the number of sugar crystals in 1.2 kg of sugar be y.
Since 2 kg of sugar contains $9\times {10}^6$crystals.

$So,\frac{2}{9\times {10}^6}=\frac{1.2}{y}$

$y=5.4\times {10}^{6}crystalsin1.2kgofsugar.$