Suppose 60 litre steel gasoline tank is full of gas that is cool because it has just been pumped from an underground reservoir. Now, both the tank and the gasoline have a temperature of $15^{\circ} C$ . How much gasoline has spilled by the time they warm to $35^{\circ} C$ ?
[ $β_{g a s} = 950 \times 10^{- 6} /^{\circ} C$ and $β_{s t e e l} = 35^{\circ} 10^{- 6} /^{\circ} C$ ]

0.5 litre

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1.1 litre

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2 litre

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2.7 litre

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Solution

The correct option is B 1.1 litre
$Δ V_{s p i l l e d} = (β_{g a s} - β_{s t e e l}) \times V \times Δ T$

$= (950 - 35) \times 10^{- 6} \times 60 \times 20$

= 1.1 litre

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