Question

Suppose 60 litre steel gasoline tank is full of gas that is cool because it has just been pumped from an underground reservoir. Now, both the tank and the gasoline have a temperature of ${15}^{\circ }C$. How much gasoline has spilled by the time they warm to ${35}^{\circ }C$?
[${\beta }_{gas}=950\times {10}^{-6}{/}^{\circ }C$ and ${\beta }_{steel}={35}^{\circ }{10}^{-6}{/}^{\circ }C$]

• A. 0.5 litre
• B. 1.1 litre
• C. 2 litre
• D. 2.7 litre

Answer 1

The correct option is B 1.1 litre

$\Delta V_{spilled}=({\beta }_{gas}-{\beta }_{steel})\times V\times \Delta T$

$=(950-35)\times {10}^{-6}\times 60\times 20$

= 1.1 litre