Suppose A1, A2,.....................A30 are thirty sets each having 5 elements and B1, B2,................Bn are n sets each with 3 elements, let 30⋃i=1Ai=n⋃j=1Bj=S and each element of S belongs to exactly 10 of Ai'S and exactly 9 of the Bj'S. Then n is equal to
45
Since S =30⋃i=1Ai
Now, element in the union S belongs to exactly 10 of the Ai'S. So n(S) = 110(5×30)=15 Again, S =n⋃j=1Bj
So, n(S) = 19(3×n) = n3 Thus,n3 = 15 ∴ n = 45