Suppose a 2- a 3- a 4- a 5- a 6- a 7 are integers such that 5-7- a 2-2 - a 3-3 - a 4-4 - a 5-5 - a 6-6 - a 7-7 - where 0 - a - j for j -2-4-5-6-7The sum a 2- a 3- a 4- a 5- a 6- a 7 isA- 8B- 9C- 10D- 11

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Real Valued Functions

Suppose a 2, ...

Question

Suppose $a_{2}, a_{3}, a_{4}, a_{5}, a_{6}, a_{7}$ are integers such that $\frac{5}{7} = \frac{a_{2}}{2!} + \frac{a_{3}}{3!} + \frac{a_{4}}{4!} + \frac{a_{5}}{5!} + \frac{a_{6}}{6!} + \frac{a_{7}}{7!}$ where 0 $\leq$ a< j for j= 2,4,5,6,7.

The sum $a_{2} + a_{3} + a_{4} + a_{5} + a_{6} + a_{7}$ is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
9

$\frac{5}{7} = \frac{2520 a_{2} + 840 a_{3} + 210 a_{4} + 42 a_{5} + 7 a_{6} + a_{7}}{7!}$

$2520 a_{2} + 840 a_{3} + 210 a_{4} + 42 a_{5} + 7 a_{6} + a_{7} = 3600$

Let $a_{2} = a_{3} = a_{4} = 1 a_{5} = 0 a_{6} = 4 a_{7} = 2$

Suggest Corrections

Similar questions

Q. Suppose

a_{2}, a_{3}, a_{4}, a_{5}, a_{6}, a_{7}

are integers such that

\frac{5}{7} = \frac{a_{2}}{2!} + \frac{a_{3}}{3!} + \frac{a_{4}}{4} + \frac{a_{5}}{5!} + \frac{a_{6}}{6!} + \frac{a_{7}}{7!}

where

0 \leq a < j

for

j = 2, 4, 5, 6, 7.

The sum

a_{2} + a_{3} + a_{4} + a_{5} + a_{6} + a_{7}

Q. Suppose

a_{2}, a_{3}, a_{4}, a_{5}, a_{6}, a_{7}

are intagers such that

\frac{5}{7} = \frac{a_{2}}{2!} + \frac{a_{3}}{3!} + \frac{a_{4}}{4!} + \frac{a_{5}}{5!} + \frac{a_{6}}{6!} + \frac{a_{7}}{7!}

where

0 \leq a_{j} < j

for

j = 2, 3, 4, 5, 6, 7

. The sum

a_{2} + a_{3} + a_{4} + a_{5} + a_{6} + a_{7}

is-

Suppose $a_{2}, a_{3}, a_{4}, a_{5}, a_{6}, a_{7}$ are integers such that $\frac{5}{7} = \frac{a_{2}}{2!} + \frac{a_{3}}{3!} + \frac{a_{4}}{4!} + \frac{a_{5}}{5!} + \frac{a_{6}}{6!} + \frac{a_{7}}{7!}$ where 0 $\leq$ a< j for j= 2,4,5,6,7.

The sum $a_{2} + a_{3} + a_{4} + a_{5} + a_{6} + a_{7}$ is

Q. Let

a_{1}, a_{2}, a_{3}, \dots

be an A.P. such that

a_{3} + a_{5} + a_{8} = 11

and

a_{4} + a_{2} = - 2

. Then the value of

a_{1} + a_{6} + a_{7}

Q. For an A.P.,

a_{1}, a_{2}, a_{3}, \dots \dots

, if

a_{3} + a_{5} + a_{8} = 11

and

a_{4} + a_{2} = - 2

, then the value of

a_{1} + a_{6} + a_{7}

Join BYJU'S Learning Program

Suppose a2,a3,a4,a5,a6,a7are integers such that 57=a22!+a33!+a44!+a55!+a66!+a77! where 0 ≤ a< j for j= 2,4,5,6,7. The sum a2+a3+a4+a5+a6+a7 is

The correct option is B 9 57=2520a2+840a3+210a4+42a5+7a6+a77! 2520a2+840a3+210a4+42a5+7a6+a7=3600 Let a2=a3=a4=1 a5=0 a6=4 a7=2

Suppose $a_{2}, a_{3}, a_{4}, a_{5}, a_{6}, a_{7}$ are integers such that $\frac{5}{7} = \frac{a_{2}}{2!} + \frac{a_{3}}{3!} + \frac{a_{4}}{4!} + \frac{a_{5}}{5!} + \frac{a_{6}}{6!} + \frac{a_{7}}{7!}$ where 0 $\leq$ a< j for j= 2,4,5,6,7.

The sum $a_{2} + a_{3} + a_{4} + a_{5} + a_{6} + a_{7}$ is

The correct option is B
9

$\frac{5}{7} = \frac{2520 a_{2} + 840 a_{3} + 210 a_{4} + 42 a_{5} + 7 a_{6} + a_{7}}{7!}$

$2520 a_{2} + 840 a_{3} + 210 a_{4} + 42 a_{5} + 7 a_{6} + a_{7} = 3600$

Let $a_{2} = a_{3} = a_{4} = 1 a_{5} = 0 a_{6} = 4 a_{7} = 2$