Suppose a and b are rational roots, and α,βbe the roots of x2+2ax+b=0, then the equation with rational coefficients one of whose roots is α+β+ 2√α2+β2 is
x2+ 4ax +2b=0
We have , α+β= -2a , αβ= b
Let y= α+β+ 2√α2+β2
=> y = -2a +2√(α+β)2−2αβ
=> (y+2a)2 = (−2a)2 -2b
=>y2+ 4a2+4ay= 4a2-2b
=> y2+ 4ay+2b =0
Changing y to x , we have x2+ 4ax +2b=0
This is the required equation .