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Question

Suppose a and b are rational roots, and α,βbe the roots of x2+2ax+b=0, then the equation with rational coefficients one of whose roots is α+β+ 2α2+β2 is


A

x2+ 4ax +2b=0

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B

x2+ 4ax -2b=0

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C

x2 _ 4ax +2b=0

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D

x2_ 4ax -2b=0

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Solution

The correct option is A

x2+ 4ax +2b=0


We have , α+β= -2a , αβ= b

Let y= α+β+ 2α2+β2

=> y = -2a +2(α+β)22αβ

=> (y+2a)2 = (2a)2 -2b

=>y2+ 4a2+4ay= 4a2-2b

=> y2+ 4ay+2b =0

Changing y to x , we have x2+ 4ax +2b=0

This is the required equation .


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