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Question

Suppose A and B are two angles such that A,Bϵ(0,π), and satisfy sinA+sinB=1 and cosA+cosB=0 . Then the value of 12cos2A+4cos2B is ________.

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Solution

cosA+cosB=0A+B=πsinA+sinB=1sinA=12=sinB12[12sin2A]+4[12sin2B]=12[124]+4[124]=6+4×12=8

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