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Question

Suppose a,b,c are positive integers such that 2a+4b+8c=328. Then a+2b+3cabc is equal to

A
12
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B
58
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C
1724
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D
56
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Solution

The correct option is C 1724
2a+4b+8c=3282a(1+22ba+23ca)=23.41
compare a=3
22ba+23ca=23+25
Either 2ba=3 and 3ca=5c=83
This is not possible.
Or 2ba=5 and 3ca=3
b=4,c=2

a=3,b=4,c=2
a+2b+3cabc=1724

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