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Question

Suppose a,b,c are real numbers, and each of the equations x2+2ax+b2=0 and x2+2bx+c2=0 has two distinct real roots. Then the equation x2+2cx+a2=0 has

A
two distinct positive real roots
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B
two equal roots
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C
one positive and one negativeroot
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D
no real roots
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Solution

The correct option is D no real roots
As the first two equations has real roots ;

4a2b4>0a2>b4/4

4b2c4>0b2>c4/4b2/4>c4/16

Combining both equations, we get a2>c4/16, also a4>c8/256

Discriminant of 3rd equation is :4c2a4

As a4>c8/256 which is much larger than 4c2,descriminant is negative
no real roots for 3rd equation

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