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Question

Suppose a,b,c are real numbers, and each of the equations x2+2ax+b2=0 and x2+2bx+c2=0 has two distinct real roots. then the equation x2+2cx+a2=0 has

A
Two distinct positive real roots
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B
Two equal roots
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C
One positive and one negative root
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D
No real roots
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Solution

The correct option is B No real roots
Now the equations have distinct real roots,
So x2+2ax+b2=0a2>b2 gives
And x2+2bx+c2=0 gives
b2>c2
from both we get a2>c2
Now for the equation x2+2cx+a2=0
we have D=c2a2<0
So no real roots.
(D)

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