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Question

Suppose a,b,c are three non-zero real numbers. Then the equation x2+(a+b+c)x+a2+b2+c2=0 has

A
rational and unequal roots.
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B
irrational roots.
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C
rational and equal roots.
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D
no real roots.
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Solution

The correct option is D no real roots.
x2+(a+b+c)x+a2+b2+c2=0
Δ=(a+b+c)24(a2+b2+c2)
=3a23b23c2+2ab+2bc+2ca
=[3a2+3b2+3c22ab2bc2ca]
=[(ab)2+(bc)2+(ca)2+a2+b2+c2]
Δ<0
Hence, the roots are non-real.

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