Suppose a,b,c are three non-zero real numbers. Then the equation x2+(a+b+c)x+a2+b2+c2=0 has
A
rational and unequal roots.
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B
irrational roots.
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C
rational and equal roots.
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D
no real roots.
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Solution
The correct option is D no real roots. x2+(a+b+c)x+a2+b2+c2=0 Δ=(a+b+c)2−4(a2+b2+c2) =−3a2−3b2−3c2+2ab+2bc+2ca =−[3a2+3b2+3c2−2ab−2bc−2ca] =−[(a−b)2+(b−c)2+(c−a)2+a2+b2+c2] ⇒Δ<0 Hence, the roots are non-real.