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Question

Suppose a,b denotes the distinct real roots of the quadratic polynomial x2+20x2020 and suppose c,d denotes the distinct complex roots of the quadratic polynomial x220x+2020.
Then the value of ac(ac)+ad(ad)+bc(bc)+bd(bd) is

A
0
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B
8000
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C
8080
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D
16000
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Solution

The correct option is D 16000
x2+20x2020=0 has two roots a,bR.
a+b=20 & ab=2020
& x220x+2020=0 has two roots c,d complex.
c+d=20 & cd=2020
now
=ac(ac)+ad(ad)+bc(bc)+bd(bd)
=a2cac2+a2dad2+b2cbc2+b2dbd2
=a2(c+d)+b2(c+d)c2(a+b)d2(a+b)
=(a2+b2)(c+d)(a+b)(c2+d2)
=[(a+b)22ab](c+d)[(c+d)22cd](a+b)
Put value a,b,c & d then,
=[(20)22(2020)](20)[(20)22(2020)](20)
=[(400+4040)](20)(20)[(20)24040]
=20[44403640]
=20[800]=16000

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