Suppose a,b denotes the distinct real roots of the quadratic polynomial x2+20x−2020 and suppose c,d denotes the distinct complex roots of the quadratic polynomial x2−20x+2020.
Then the value of ac(a−c)+ad(a−d)+bc(b−c)+bd(b−d) is
A
0
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B
8000
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C
8080
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D
16000
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Solution
The correct option is D16000 x2+20x−2020=0 has two roots a,b∈R. a+b=−20 & a⋅b=−2020
& x2−20x+2020=0 has two roots c,d∈ complex. c+d=20 & c⋅d=2020
now =ac(a−c)+ad(a−d)+bc(b−c)+bd(b−d) =a2c−ac2+a2d−ad2+b2c−bc2+b2d−bd2 =a2(c+d)+b2(c+d)−c2(a+b)−d2(a+b) =(a2+b2)(c+d)−(a+b)(c2+d2) =[(a+b)2−2ab](c+d)−[(c+d)2−2cd](a+b)
Put value a,b,c & d then, =[(−20)2−2(−2020)](20)−[(20)2−2(2020)](−20) =[(400+4040)](20)−(−20)[(20)2−4040] =20[4440−3640] =20[800]=16000