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Question

Suppose a block of mass 1 kg is placed over a rough surface and a horizontal force F is applied on the block as shown in figure. Now, let us see what are the values of force of friction f and acceleration of the block a if the force F is gradually increased. Given that μs=0.5,μk=0.4 and (g= 10m/s2).
245557_394771152ba545658349a6d7dbb87f6f.png

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Solution

From the graph it is clear that the maximum frictional force we can get is maximum static friction
fs=μsN
fs=0.5×1×10
fs=5N

After this if we increase the force the block will start moving and there is a constant frictional force will act on the block that force is call kinetic frictional force and the value of kinetic frictional force is
fk=μkN
fs=0.4×1×10
fs=4N

now the acceleration the block will be
a=FμkNM
a=F41
acceleration (a)=F4

596725_245557_ans_982f3bdf01ea44529a9ccab54c2f1203.png

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