Suppose a hammer of mass 1 kg is falling freely on the wooden block, if the hammer fall from a height of 1 m. How much kinetic energy just before hitting the wooden block?

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Solution

Given,
$h = 1 m m = 1 k g$

When hammer will reach on the ground, its potential energy will convert into kinetic energy.
From conservation of energy,
Loss in potential energy = Gain in kinetic energy
$m g h = K . E$
$K . E = 1 \times 10 \times 1 = 10 N - m o r j u l$

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Suppose a hammer of mass 1 kg is falling freely on the wooden block, if the hammer fall from a height of 1 m. How much kinetic energy just before hitting the wooden block?

Given,h=1 mm=1 kgWhen hammer will reach on the ground, its potential energy will convert into kinetic energy.From conservation of energy,Loss in potential energy = Gain in kinetic energymgh=K.EK.E=1×10×1=10 N−m or jul

Given,
$h = 1 m m = 1 k g$

When hammer will reach on the ground, its potential energy will convert into kinetic energy.
From conservation of energy,
Loss in potential energy = Gain in kinetic energy
$m g h = K . E$
$K . E = 1 \times 10 \times 1 = 10 N - m o r j u l$