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Question

Suppose a lot of n objects having n1 objects of one kind, n2 objects are of second kind, n3 objects of third kind, .... , nk objects of kth kind satisfying the condition n1+n2....+nk=n, then the number of possible arrangements/permutation of m objects out of this lot is the coefficient of xm in the expansion of m!{a1λ=0xλλ!}

The number of permutations of the letters of the word SURITI taken 4 at a time is

A
360
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B
240
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C
216
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D
192
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Solution

The correct option is D 192
Given word : SURITI

I=2 times

S,U,R,T=1-times

case - I ; All letters are different

Number of arrangement = 5C4×4!
=5×24
=120

case - II ; two are different and two are same kind
Number of arrangement = 4C2×4!2!
=6×242=72
total arrangement = 120+72=192

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