Suppose a particle $a$ of charge $2 e$ and mass $2 m_{e}$ ( $m_{e}$ being mass of electron) revolves around the proton in nearest allowed circular orbit of radius r. If the radius of first Bohr orbit for the electron is $A_{0}$ , then the relation between $r$ and $a_{0}$ is

a_{0}

4 r

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a_{0}

8 r

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a_{0}

2 r

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a_{0}

\frac{r}{4}

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Solution

The correct option is C $a_{0}$ = $4 r$
$r = a_{o} \frac{n^{2}}{Z^{2}}$

Here $n = 1, Z = 2$

This gives us $a_{o} = 4 r$

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