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Question

Suppose ABCD is a rectangle whose diagonals AC and BD intersect at O. If OAB=62, find OBC

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Solution

The diagonals of a rectangle are equal and bisect each other. So,
OA=OB
OBA=OAB=62 (angles opposite to equal sides are equal)
Since the measure of each angle of rectangle is 90
ABC=90
ABO+OBC=90
62+OBC=90
OBC=9062=28

1066434_620419_ans_933f8c8a93f8418191c9d4485669c253.jpg

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