Question

Suppose ABCD is rectangle. Using RHS theorem, prove that triangles ABC and ADC are congruent.

Answer 1

Given: AB = DC, AD = BC and ∠A = ∠B = ∠C = ∠D = 90°

To Prove: ΔADC ≅ ΔABC

Proof:

In ΔADC and ΔABC:

AD = BC (Given)

∠D = ∠B = 90° (Given)

AC = AC (Common)

∴ ΔADC ≅ ΔABC (RHS congruency)