Question

Suppose all the electrons of 100 g water are lumped together to form a negatively hcarged particle and all the nuclei are lumped together to form a positively harged particle. If these two particles are plaed 10.0 cm away from each other, find the force of attraction between them. compare it with your weight.

Answer 1

No. of electrons in 10 gm $H_{2}O$
$=3.34\times {10}^{25}$
and total charge of electrons in 100 gm
water = $-5.34\times {10}^{6}C$
Similarly, total charge of protons in 100
gm water $=+5.34\times {10}^{6}C$
Hence electrical force
$=9\times {10}^9\times \frac{5.34\times {10}^6\times 5.34\times {10}^6}{{10}^{-2}}=2.56\times {10}^{25}$
Newtons