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Question

Suppose an orbital may accommodate three electrons, then the number of elements in 4th period will be:

A
12
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B
27
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C
18
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D
32
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Solution

The correct option is B 27
In the fourth period of the periodic table, there is a filling of 4s,3d,4p orbitals. So the total number of orbitals to be filled =1(4s)+5(3d)+3(4p)=9

If each orbital can hold a maximum of 3 electrons the number of elements=3×9=27

Hence option B is the correct answer.

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