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Byju's Answer
Standard X
Mathematics
Range of Trigonometric Ratios from 0 to 90 Degrees
Suppose cos...
Question
Suppose
cos
A
is given. If only one value of
cos
(
A
2
)
is possible, then
A
must be
A
An odd multiple of
90
o
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B
A multiple of
90
o
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C
An odd multiple of
180
o
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D
A multiple of
180
o
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Solution
The correct option is
C
An odd multiple of
180
o
2
cos
2
A
2
−
1
=
cos
A
⇒
2
cos
2
A
2
=
cos
A
+
1
⇒
cos
A
2
=
±
√
1
+
cos
A
2
If one value of
A
possible then
cos
A
must be
′
−
1
′
, therefore
′
A
′
must be odd multiple
180
o
Suggest Corrections
0
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