Supposep,q,r≠0 and the system of equations (p+a)x+by+cz=0ax+(q+b)y+cz=0ax+by+(r+c)z=0 has a non-trivial solution,then the value of pa+qb+rc,is
A
-1
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B
0
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C
1
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D
2
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Solution
The correct option is B -1 For non-trivial solution, ∣∣
∣∣p+abcaq+bcabr+c∣∣
∣∣=0 R1→R1−R2,R2→R2−R3 ∣∣
∣∣p−q00q−rabr+c∣∣
∣∣=0 ⇒pqr+pqc+pbr+aqr=0 ⇒cr+bq+ap=−1