Suppose f is a real function satisfying f(x+f(x))=4f(x) and f(1)=4. Find the value of f(21).
Given, f(x+f(x))=4f(x) & f(1)=4
Substituting X=1 we get f(1+f(1))=4f(1)⇒f(1+4)=16⇒f(5)=16
Now substitute x=5, f(5+f(5))=4f(5)⇒f(5+16)=64=f(21)