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Question

Suppose f is a real function satisfying f(x+f(x))=4f(x) and f(1)=4. Find the value of f(21).

A
16
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B
64
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C
21
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D
80
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Solution

The correct option is C 64

Given, f(x+f(x))=4f(x) & f(1)=4

Substituting X=1 we get f(1+f(1))=4f(1)f(1+4)=16f(5)=16

Now substitute x=5, f(5+f(5))=4f(5)f(5+16)=64=f(21)


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