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Question

Suppose for fixed real numbers a and b f(x)=x3+ax2+bx+c has 3 distinct roots for c=0. Then

A
fc(x) has 3 distinct roots for all real c
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B
fc(x) has 3 distinct roots for all real c>0 or for all real c<0 but not for both
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C
fc(x) has 3 distinct roots for all real c in (p,q) for some p<0 and q>0
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D
fc(x) need not have 3 distinct roots for any real c other than zero
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Solution

The correct option is D fc(x) need not have 3 distinct roots for any real c other than zero

The point here is to reduce the equation to

x2(xa)+bxc=0

Now if b=1, the equation becomes

(x2+1)+(xc)=0

The above equation has one real and two imaginary roots and hence does not satisfy the condition given in the question (3 real roots)

Therefore b cannot be equal to 1.


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