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Question

Suppose n is an integer such that the sum of the digits of n is 2, and 1010 < n < 1011. The number of different values for n is :(CAT 2004)

A
11
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B
10
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C
9
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D
8
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Solution

The correct option is A 11

Option (a)

There are 11 digits in this number

When sum of digits is 2, there are 2 options

There are 2 ones, with one 1 fixed in the first position

The question in now based on the arrangement of 10 zeroes and 1 one

Number of possibilities = = 10 ways

When 2 is the first digit = one possibility.

Total number of possibilities = 11


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