Question

Suppose NTP is used in place of STP. What will be the change in molar volume of a gas if the new condition is defined by doubling the temperature as well as pressure?

• A. Molar volume will remain unchanged
• B. Molar volume will become half
• C. Molar volume will double itself
• D. Molar volume will become 0.54 times the earlier one

Answer 1

The correct option is D Molar volume will become 0.54 times the earlier one

NTP condition is at ${25}^0$C temperature and $1$ atm pressure.
So, Volume$=\frac{n\times R\times T}{P}$
$V=\frac{1\times R\times \times 298}{1}$

New condition is at ${50}^0$C and $2$atm pressure.
$V^{\prime }=\frac{1\times R\times 323}{2}$
Therefore,$\frac{V^{\prime }}{V}=0.5419$