Question:- suppose one millikans oil drop contains -4.8 * 10 to the power -19 . How excess electrons are present in one such drop?

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Solution

Given the charge on millikan drop=-4.810^-19 coulomb.
Let n be number of electrons then.
n1.610^-19 =4.810^-19
Solving it we get n=3 answer.

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Question:- suppose one millikans oil drop contains -4.8 * 10 to the power -19 . How excess electrons are present in one such drop?

Given the charge on millikan drop=-4.8*10^-19 coulomb. Let n be number of electrons then. n*1.6*10^-19 =4.8*10^-19 Solving it we get n=3 answer.

Given the charge on millikan drop=-4.810^-19 coulomb.
Let n be number of electrons then.
n1.610^-19 =4.810^-19
Solving it we get n=3 answer.