Suppose refractive index - is given as - - A - B-2where A and B are constants and - is wavelength- then dimensions of B are same as that of

The correct option is D Area μ =A+ B λ #160; ^ 2 . #160; Equating dimensions give #160; B λ #160; ^ 2 = M ^ 0 L ^ 0 T ^ 0 ⇒ B= M ^ 0 L ...

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Standard X

Physics

Apparent Depth

Suppose refra...

Question

Suppose refractive index $μ$ is given as
$μ = A + \frac{B}{λ^{2}}$
where A and B are constants and $λ$ is wavelength, then dimensions of B are same as that of

Wavelength

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Volume

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Pressure

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Area

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Solution

The correct option is D Area
$μ = A + \frac{B}{λ^{2}}$ . Equating dimensions give $\frac{B}{λ^{2}} = M^{0} L^{0} T^{0}$
$\Rightarrow B = M^{0} L^{2} T^{0} \to$ same as dimension of area.

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Suppose refractive index μ is given asμ=A+Bλ2where A and B are constants and λ is wavelength, then dimensions of B are same as that of

The correct option is D Areaμ=A+Bλ2. Equating dimensions give Bλ2=M0L0T0⇒B=M0L2T0→ same as dimension of area.

Suppose refractive index $μ$ is given as
$μ = A + \frac{B}{λ^{2}}$
where A and B are constants and $λ$ is wavelength, then dimensions of B are same as that of

The correct option is D Area
$μ = A + \frac{B}{λ^{2}}$ . Equating dimensions give $\frac{B}{λ^{2}} = M^{0} L^{0} T^{0}$
$\Rightarrow B = M^{0} L^{2} T^{0} \to$ same as dimension of area.