Question

Suppose Swarglok (heaven) is in constant motion at a speed of 0.9999c with respect to the earth. According to the earth's frame, how much time passes on the earth before one day passes on Swarglok?

Answer 1

Given : $v=0.9999c$

Time elapsed on Swarglok $\tau =1$ day

$\therefore$ Time passed on earth $t=\frac{\tau }{\sqrt{1-(v/c{)}^2}}$

$\therefore$ $t=\frac{1}{\sqrt{1-(0.9999{)}^2}}$ $=70.7$ days