Question

Suppose that a box is accelerating at a rate of $2\frac{m}{s^2}$. If the net force is tripled and the mass is doubled, then what is the new acceleration of the box?

___$\frac{m}{s^2}$.

Answer 1

Let F be the force acting on the body with mass M.

given acceleration $a=2\frac{m}{s^2}$

$F=Ma$

$⟹a=\frac{F}{M}=2\frac{m}{s^2}----\left(1\right)$

Now, the force is tripple and mass is doubled.

$F_1=3F,M_1=2M$

$a_1$ be the new acceleration

$F_1=M_1{a}_1$

$⟹a_1=\frac{F_1}{M_1}=\frac{3F}{2M}$

From (1) the value of $\frac{F}{M}=2$

$⟹a_1=\frac{3}{2}\times 2=3\frac{m}{s^2}$