Suppose that a boy skates at a rate of $2 m s^{- 2}$ . If the net force is tripled and the mass is halved, then what is the new acceleration of the skater?

12 m s^{- 2}

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6 m s^{- 2}

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1 m s^{- 2}

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9 m s^{- 2}

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Solution

The correct option is A $12 m s^{- 2}$
According to the question, force $F$ is tripled and mass $m$ is halved.
Let $a$ be the acceleration of the boy.
Using the formula $F = m \times a$
$3 \times F = \frac{m}{2} \times a$
or the new value of acceleration is 6 times the original.
i.e. $12 m s^{- 2}$ .

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Suppose that a boy skates at a rate of 2 ms−2. If the net force is tripled and the mass is halved, then what is the new acceleration of the skater?

The correct option is A 12 ms−2According to the question, force F is tripled and mass m is halved. Let a be the acceleration of the boy. Using the formula F=m×a 3×F=m2×a or the new value of acceleration is 6 times the original. i.e. 12ms−2.

Suppose that a boy skates at a rate of $2 m s^{- 2}$ . If the net force is tripled and the mass is halved, then what is the new acceleration of the skater?