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Question

Suppose that a quadratic polynomial x2+bx+1,bR, has two zeros which are both real then which one of the following is necessarily true?

A
b can have infinitely many values
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B
b has a unique value
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C
b has atmost two distinct values
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D
b has atmost four distinct values
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Solution

The correct option is A b can have infinitely many values
x2+bx+1:bR
Comparing it with general form of quadratic equation ax2+bx+c=0,
we have a=1,b=b,c=1
Given that roots are real, the discriminant will have to be non-negative.
D=b24ac0
b240
(b2)(b+2)0
(b+2)0 or (b2)0
b2 or b2
b has infinitely many values

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