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Question

Suppose that a reaction has ΔH=40 kJ and ΔS=50 kJ/K. At what temperature range will it change from spontaneous to non-spontaneous?

A
0.8 K to 1 K
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B
799 K to 800 K
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C
800 K to 801 K
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D
799 K to 801 K
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Solution

The correct option is A 0.8 K to 1 K
ΔG=ΔHTΔS
ΔH=40 kJ
ΔS=50 kJ/K
if ΔG<0, process is spontaneous
if ΔG>0, process is non spontaneous
if ΔG=0, process is in equilibrium
For T=0.8K
ΔG=400.8×50=0
ΔG=0
The process is in equilibrium
For T=1K
ΔG=401×50=10
The process is in spontaneous

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