Question

Suppose that a T-NC pizza cost as much as a D-NC pizza, but $\frac{3}{5}th$ of the price of a D-EC pizza. A D-EC pizza costs Rs 50 more than a T-EC pizza, and the latter costs Rs. 500.
If 25% of the Normal Cheese pizzas delivered to Party 1 were of Deep Dish variety, what was the total bill for Party 1?

• A. 59480
• B. 59840
• C. 42520
• D. 45240

Answer 1

The correct option is A 59480

Given, Number of pizzas to be delivered to Party $3=0.7\times 800=560$
Number of pizzas to be delivered to Party 2 = Number of pizzas to be delivered to Party $1=\frac{(800-560)}{2}=120$
Refer to the table below:
$\begin{array}{ccc}Party& ThinCrust\left(T\right)& NormalCheese\left(NC\right)\\ 1& 0.6\times 120=72& 416-36-364=16\\ 2& 0.55\times 120=66& 0.3\times 120=36\\ 3& 300-72-66=162& 0.65\times 560=364\\ Total& 0.375\times 800=300& 0.52\times 800=416\end{array}$
Given, for Party 1,
$D-NC=\left(\frac{1}{4}\right)\times 16=4$
T-NC = 16 - 4 = 12
T-NC + T-EC = 72
T-EC = 72 - 12 = 60g
D-EC + D-NC + T-NC + T-EC = 120
D-EC + 4 + 12 + 60 = 120
D-EC = 44
Cost of 1 T-EC pizza = Rs. 500
Therefore, cost of 60 T-EC pizza =$60\times 500$ = Rs. 30000
Cost of 1 D-EC pizza = Rs. 550
Therefore, cost of 44 D-EC pizza $=44\times 550$ = Rs. 24200
Cost of 1 T-NC pizza = Cost of 1 D-NC pizza $=\left(\frac{3}{5}\right)\times 550$ = Rs. 330
Therefore, cost of 12 T-NC pizza & 4 D-NC pizza =$16\times 330$ = Rs. 5280
Hence, Total bill for Party 1 = 30000 + 24200 + 5280 = Rs. 59480