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Question

Suppose that f is a polynomial of degree 3 and that f′′(x)0 at any of the stationary point. Then

A
f has exactly one stationary point
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B
f must have no stationary point
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C
f must have exactly 2 stationary point
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D
f has exactly 0 or 2 stationary point.
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Solution

The correct option is D f has exactly 0 or 2 stationary point.
The given information is a polynomial of degree 3.

Let the function be f(x)=ax3+bx2+cx+d.

To find the stationary points we differentiate and equate it to zero.

f(x)=3ax2+2bx+x

The differentiated function is a quadratic equation which will give two real or two complex roots. If we get two real roots then we will have exactly 2 stationary points. Now if the roots are complex as they always occur in pair then we have no stationary points. Thus f has exactly 0 or 2 stationary points. .....Answer

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