Suppose that f(x) is continuous in [1,2] such that f(x)=0 has atleast one real solution in (1,2), then
A
f(1)⋅f(2)=0
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B
f(1)⋅f(2)≥0
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C
f(1)⋅f(2)>0
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D
f(1)⋅f(2)<0
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Solution
The correct option is Df(1)⋅f(2)<0 ∵f(x) is continuous in [1,2]
Then from I.V.T., there is atleast one real solution for f(x)=0 in (a,b),
If f(a)⋅f(b)<0