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Byju's Answer
Standard XII
Mathematics
Composite Function
Suppose that ...
Question
Suppose that function
f
:
R
→
R
satisfies
f
(
x
+
y
)
=
f
(
x
)
f
(
y
)
for all
x
,
y
∈
R
and
f
(
1
)
=
3
.If
∑
n
i
=
1
f
(
i
)
=
363
, then
n
is equal to
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Solution
f
(
x
+
y
)
=
f
(
x
)
f
(
y
)
f
(
x
)
=
a
x
⇒
f
(
1
)
=
a
=
3
f
(
x
)
=
3
x
∑
n
i
=
1
f
(
i
)
=
363
⇒
3
+
3
2
+
3
3
+
.
.
.
.
+
3
n
=
363
⇒
3
(
3
n
−
1
)
2
=
363
⇒
n
=
5
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1
Similar questions
Q.
If
f
:
R
→
R
satisfies
f
(
x
+
y
)
=
f
(
x
)
+
f
(
y
)
, for all
x
,
y
∈
R
and
f
(
1
)
=
7
,then
∑
n
r
=
1
f
(
r
)
is
Q.
Let
f
:
R
→
R
be a function which satisfies
f
(
x
+
y
)
=
f
(
x
)
+
f
(
y
)
∀
x
,
y
∈
R
. If
f
(
1
)
=
2
and
g
(
n
)
=
(
n
−
1
)
∑
k
=
1
f
(
k
)
,
n
∈
N
then the value of
n
, for which
g
(
n
)
=
20
, is:
Q.
If
f
(
x
)
is function satisfying
f
(
x
+
y
)
=
f
(
x
)
f
(
y
)
for all
x
,
y
,
∈
N such that
f
(
1
)
=
3
and
∑
n
x
=
1
f
(
x
)
=
120.
Then the value of
n
is.
Q.
Let
f
:
R
→
R
be a continuous function satisfying
f
(
0
)
=
1
and
f
(
2
x
)
−
f
(
x
)
=
x
, for all
x
∈
R
.
Then
f
(
2020
)
equals
Q.
Let
f
:
R
→
R
be a differentiable function satisfying
f
(
x
+
y
)
=
f
(
x
)
+
f
(
y
)
+
x
y
for all
x
,
y
∈
R
and
lim
h
→
0
1
h
f
(
h
)
=
3.
If the minimum value of
f
(
x
)
is
k
, then the value of
|
2
k
|
is
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