Suppose that it takes a simple pendulum 1.2 seconds to swing from its leftmost point to its rightmost point. What is the period of the pendulum?

0.6 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.2 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.4 s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3.6 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
2.4 s

The period of a pendulum is the amount of time required for the pendulum to complete one full back-and-forth motion, from its rightmost point back to its rightmost point again. The time required to swing from its rightmost point to its leftmost point is half of a period. It will require the same amount of time to swing back, so the period is 2.4 s.

Suggest Corrections

Similar questions

The pendulum is released from P. It takes 0.2 s to swing from P to Q and takes another 0.2 s to swing from Q to R. The pendulum is at its lowest point at R. What is the frequency of pendulum?

A simple pendulum takes 20 seconds to complete 12 oscillations. Calculate its time period. What type of motion does the pendulum undergo? [3 MARKS]

Q. The bob of a simple pendulum takes 2 seconds to go from one extreme position to the mean position. What is the time period of the simple pendulum?

Q. A simple pendulum has a time period

T = 2 sec

when it swings freely.The pendulum is hung as shown in the figure, so that only one-fourth of its total length is free to swing to the left of the obstacle.It is displaced to position

A

and released.If it takes

\frac{x}{2} sec

to swing to extreme displacement B and return to

A

. Find

x (

Assume that displacement angle is always small

)

Q. A freely falling body takes

2

seconds to reach the ground on a planet when it is dropped from, a height of

8 m

. If the period of a simple pendulum is

2

seconds on that planet then its length is:

Join BYJU'S Learning Program