Question

Suppose that the electric field amplitude of an electromagnetic wave is $E_0=120N/C$ and that its frequency is $\nu =50.0MHz$.

(a) Determine, $B_0,\omega ,k,and\lambda$

(b) Find the expression for E and B.

Answer 1

(a)

$B_o=E_o/c=400nT$

$\omega =2\pi \nu =3.14\times {10}^{8}rad/s.$

$k=\omega /c=1.05$ rad/m

$\lambda =c/\nu =6m$

(b)

Suppose wave is moving along x-direction, Electric field be along y-direction and magnetic field along the z-direction.

$E=E_{o}sin(kx-\omega t)\hat{j}=120sin(1.05x-3.14\times {10}^{8}t)\hat{j}$

Similarly,

$B=4\times {10}^{-7}sin(1.05x-3.14\times {10}^{8}t)\hat{k}$