Question

Suppose that the position vector function for a particle is given as $\overrightarrow{r}\left(t\right)=x\left(t\right)\hat{i}+y\left(t\right)\hat{j}$, where $x\left(t\right)=t^2+1$ and$y\left(t\right)=\frac{t^2}{4}(x,y$ in $m$ and $t$ in sec)

• A. Average speed of the particle during the time interval t = 2.0 sec to 4.0 sec is $\left(\frac{3\sqrt{17}}{2}\right)m/s$
• B. Speed of the particle at t = 2.0 sec is $\sqrt{5}$ m/s
• C. Speed of the particle at t = 2.0 sec is $\frac{\sqrt{5}}{4}$ m/s
• D. Average speed of the particle during the time interval t = 2.0 sec to 4.0 sec is$\left(3\sqrt{17}\right)m/s$

Answer 1

The correct option is A Average speed of the particle during the time interval t = 2.0 sec to 4.0 sec is $\left(\frac{3\sqrt{17}}{2}\right)m/s$

Average speed = Total displacement/Total time