Suppose that there are three atoms A, B, C, and their oxidation number are $6, - 1, - 2$ , respectively. What will be the molecular formula of the compound?

Open in App

Solution

Three atoms A B C
Oxidation No. 6 -1 -2
When the compound contain 6 atoms of A, 4 atoms of B, and 1 atom of C we will get completely neutral compound
$1 A ⟶ (6) 4 B ⟶ (- 4) 1 C ⟶ (- 2)$
$+ 6 - 4 - 2 = 0$
$+ 6 - 6 = 0$
Therefore the molecular formula will be ${A B}_{4} C$

Suggest Corrections

Similar questions

A, B

C

+ 2, + 3

- 2

The empirical formula and molecular mass of a compound are $C H_{2} O$ and 180 g respectively. What will be the molecular formula of the compound ?

(a) $C_{9} H_{18} O_{9}$ (b) $C H_{2} O$ (c) $C_{6} H_{12} O_{6}$ (d) $C_{2} H_{4} O_{2}$

A, B, C

+ 2, + 5

- 2

Join BYJU'S Learning Program