Question

Suppose the 19 Ω resistor of the previous problem is disconnected. Find the current through P₂Q₂ in the two situations (a) and (b) of that problem.

Answer 1

(a) When the wires move in the same direction, their polarity remains the same. The circuit remains incomplete. Therefore, no current flows in the circuit.

(b) When the wires move in opposite directions, their polarities are reversed. Thus, current flows in the circuit.
$V_{{\mathrm{P}}_2{\mathrm{Q}}_2}=Blv$
= 1 × 0.04 × 0.05
= 2 × 10⁻³ V
R = 2 Ω
Current in the circuit is given by
$i=\frac{2\times {10}^{-3}}{2}$
= 1 × 10⁻³ A = 1 mA