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Kepler's Law

Suppose the a...

Question

Suppose the acceleration due to gravity at the earth's surface is $10 m / s^{2}$ and at the surface of mars it is $4.0 m / s^{2} .$ A $60 k g$ passenger goes from the earth to the mars in a spaceship moving with a constant velocity. Neglect all other object in the sky. Which part of the figure best represent the weight (net gravitational force) of the passenger as a function of time?

A

A

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B

B

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C

C

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D

D

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Solution

The correct option is A $A$
Note that there must be some point where the gravitational field of the earth is balanced by the gravitational field of Mars.

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Similar questions

Q. Suppose, the acceleration due ot gravity at the earth's surface is

10 m s^{- 2}

and at the surface of Mars it is

4.0 m s^{- 2}

60

kg passenger goes from the Earth to the Mars in a spaceship moving with a constant velocity. Neglect all other objects in the sky. Which part of figure bests represents the weight (net gravitational force) of the passenger as a function of time?

Q. Suppose,the accelaration due to gravity at the Earth's surface is

10 {m/s}^{2}

and at the surface of Mars is

4.0 {m/s}^{2}

60 kg

passenger goes from the Earth to Mars in a spaceship moving with a constant velocity. Neglect the influence of all other objects in the sky. Which of the following best represents the weight(net gravitational force)of the passenger as a function of time

Q. The acceleration due to gravity on the surface of the earthj is

10 m s^{- 2}

. The mass of the planet Mars as compared to earth is 1/10 and radius is 1/2. Determine the gravitational acceleration of a body on the surface of mars.

Q. Calculate the acceleration due to gravity at the surface of Mars if its diameter is 6760 km and mass one-tenth that of earth. The diameter of earth is 12742 km and acceleration due to gravity on earth is

9.8 m / s^{2}

Object	Acceleration Due to Gravity $(m / s^{2})$
Earth	$9.8$
Moon	$1.6$
Mars	$3.7$
Venus	$9.5$
Jupiter	$24.5$

The approximate height h of an object launched vertically upward after an elapsed time t is represented by the equation

h = - \frac{1}{2} a t^{2} + v_{0} t + h_{0}

a

is acceleration due to gravity,

v_{0}

is the object's initial velocity, and

h_{0}

is the object's initial height. The table above gives the acceleration due to gravity on Earth's moon and several planets. If two identical objects are launched vertically upward at an initial velocity of

40 m / s

from the surfaces of Mars and Earth's moon, approximately how many more seconds will it take for the moon projectile to return to the ground than the Mars projectile?

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